How `is_base_of` works?

Posted by Alexey Malistov on Stack Overflow See other posts from Stack Overflow or by Alexey Malistov
Published on 2010-05-26T07:43:28Z Indexed on 2010/05/26 9:21 UTC
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Why the following code works?

typedef char (&yes)[1];
typedef char (&no)[2];

template <typename B, typename D>
struct Host
{
  operator B*() const;
  operator D*();
};

template <typename B, typename D>
struct is_base_of
{
  template <typename T> 
  static yes check(D*, T);
  static no check(B*, int);

  static const bool value = sizeof(check(Host<B,D>(), int())) == sizeof(yes);
};

//Test sample
class Base {};
class Derived : private Base {};

//Exspression is true.
int test[is_base_of<Base,Derived>::value && !is_base_of<Derived,Base>::value];

Note that B is private base. Note that operator B*() is const. How does this work? Why this works? Why static yes check(D*, T); is better than static yes check(B*, int); ?

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